Completed Design1

[ashritha0806]

No description provided.

[super30admin]

Implement Hash Set (Hashset.py)

Strengths:

• You have correctly implemented the double hashing technique.
• You handled the edge case for primary index 0 by creating a secondary array of size 1001.
• The code is clean and well-commented.

Areas for improvement:

1. The secondary hash function: In the reference Java solution, the secondary hash uses division by secondaryBuckets (which is 1000) to get the index. However, in Python, using integer division (//) is correct. But note that for keys that are negative (if allowed) this might break. However, the constraints say key is between 0 and 10^6, so it's safe. But it's good to be aware.
2. In the contains method, you check if the primary bucket is not None and then return the value. This is correct. However, you might want to consider using and to avoid index errors. Your current code does that correctly.
3. There is a minor issue: when you create the secondary array for primary index 0, you set the size to self.items_per_bucket + 1, which is 1001. This is correct. But for other indices, you create 1000. This is exactly as required.
4. Efficiency: The solution is efficient. However, one optimization could be to avoid creating the secondary array until it is needed (which you are already doing). Also, when removing, you are setting the value to False without checking if the secondary array exists. This is efficient because if it doesn't exist, we don't need to do anything. But in your remove method, you check if the primary bucket is not None before setting. This is correct.

Overall, the solution is correct and efficient. Good job!

VERDICT: PASS

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Implement Min Stack (Minstack.py)

Your solution is correct and efficient. You have successfully implemented the MinStack with constant time operations using two stacks. The code is clean and well-commented. However, consider the following points for improvement:

1. Initialization of min_stack: In your push method, you check if min_stack is empty to push the first value. Alternatively, you could initialize min_stack with a sentinel value (like infinity) to simplify the push method. This would avoid the conditional check in every push, but it's a minor optimization and not necessary for correctness.

2. Consistency in naming: The problem uses "MinStack" as the class name, but in your code, you named it "MinStack" (with uppercase 'S') in the class definition, but in the comments you wrote "Minstack.py" (with lowercase 's'). This is a trivial point, but consistency in naming is good practice.

3. Type hints: Since you are using Python, you could add type hints for method parameters and return types to improve code clarity. For example, the push method could be defined as def push(self, val: int) -> None:.

4. Edge cases: Although the problem states that operations will be called on non-empty stacks, it's always good to consider edge cases. For example, if someone calls pop on an empty stack, your code would raise an exception. However, since the problem constraints guarantee non-empty stacks for pop, top, and getMin, this is acceptable.

Overall, your solution is excellent. Keep up the good work!

VERDICT: PASS