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65 changes: 37 additions & 28 deletions FormalConjectures/GreensOpenProblems/57.lean
Original file line number Diff line number Diff line change
Expand Up @@ -82,21 +82,6 @@ def Φ : Set (G → ℂ) :=
def Φ' : Set (G → ℂ) :=
convexHull ℝ (baseΦ' G)

/--
Is it true that for every finite abelian group $G$ the spaces $\Phi(G)$ and $\Phi'(G)$,
obtained from kernels $\phi(g) = \mathbb{E}_{x_1 + x_2 + x_3 = g} f_1(x_2, x_3)
f_2(x_1, x_3) f_3(x_1, x_2)$ with $\lVert f_i \rVert_\infty \le 1$
(where $f_i : G \times G \to \mathbb{C}$), still coincide when the
third kernel is required to depend only on $x_1 + x_2$?

Green guesses that the answer is probably 'no'.
-/
@[category research open, AMS 5 11]
theorem green_57 :
answer(sorry) ↔
∀ (G : Type) [AddCommGroup G] [Fintype G] [DecidableEq G],
Φ G = Φ' G := by
sorry

/-- The linear functional on `G → ℂ` given by `φ ↦ Re ∑ g, a g * φ g`. -/
def functional (a : G → ℂ) (φ : G → ℂ) : ℝ :=
Expand All @@ -107,32 +92,56 @@ def functional (a : G → ℂ) (φ : G → ℂ) : ℝ :=
def supportFn (a : G → ℂ) (S : Set (G → ℂ)) : ℝ :=
sSup (functional G a '' S)

/-- Do $\Phi(\mathbb{Z}/3\mathbb{Z})$ and $\Phi'(\mathbb{Z}/3\mathbb{Z})$ coincide?

Numerical evidence suggests the answer is **no**: the integer functional $a = (-1, -3, 3)$
separates the two spaces. A branch-and-bound verification over the phase variables shows
$\max_{\Phi'} \operatorname{Re}\langle a, \varphi \rangle < 6.112 < 6.115 \approx
\max_{\Phi} \operatorname{Re}\langle a, \varphi \rangle$.
-/
@[category research open, AMS 5 11]
theorem green_57.variants.z3 :
answer(sorry) ↔ (Φ (ZMod 3) = Φ' (ZMod 3)) := by
sorry

/-- For $G = \mathbb{Z}/3\mathbb{Z}$ and the functional $a(0) = -1$, $a(1) = -3$, $a(2) = 3$,
does the support function of $\Phi$ at $a$ strictly exceed that of $\Phi'$?

Numerical evidence suggests the answer is **yes**:
$$\sup_{\varphi \in \Phi'(\mathbb{Z}/3\mathbb{Z})} \operatorname{Re}\langle a, \varphi \rangle
\;<\; \sup_{\varphi \in \Phi(\mathbb{Z}/3\mathbb{Z})} \operatorname{Re}\langle a, \varphi \rangle.$$

The DeepMind prover agent provided a formal proof, showing that $\frac{183095}{30000}$ separates the
support functions.
-/
@[category research open, AMS 5 11]
@[category research solved, AMS 5 11, formal_proof using formal_conjectures at
"https://github.com/mo271/formal-conjectures/blob/f5afe85e1e02611f63c32ae041b33c67b7938cba/FormalConjectures/GreensOpenProblems/57.lean#L1071"]
theorem green_57.variants.z3_functional :
let a : ZMod 3 → ℂ := ![(-1 : ℂ), -3, 3]
answer(sorry) ↔
answer(True) ↔
Comment thread
mo271 marked this conversation as resolved.
supportFn (ZMod 3) a (Φ' (ZMod 3)) < supportFn (ZMod 3) a (Φ (ZMod 3)) := by
sorry

/-- Do $\Phi(\mathbb{Z}/3\mathbb{Z})$ and $\Phi'(\mathbb{Z}/3\mathbb{Z})$ coincide?

Numerical evidence suggests the answer is **no**: the integer functional $a = (-1, -3, 3)$
separates the two spaces. A branch-and-bound verification over the phase variables shows
$\max_{\Phi'} \operatorname{Re}\langle a, \varphi \rangle < 6.112 < 6.115 \approx
\max_{\Phi} \operatorname{Re}\langle a, \varphi \rangle$.
-/
@[category research solved, AMS 5 11, formal_proof using formal_conjectures at
"https://github.com/mo271/formal-conjectures/blob/f5afe85e1e02611f63c32ae041b33c67b7938cba/FormalConjectures/GreensOpenProblems/57.lean#L1100"]
theorem green_57.variants.z3 :
answer(False) ↔ (Φ (ZMod 3) = Φ' (ZMod 3)) := by
sorry
/--
Is it true that for every finite abelian group $G$ the spaces $\Phi(G)$ and $\Phi'(G)$,
obtained from kernels $\phi(g) = \mathbb{E}_{x_1 + x_2 + x_3 = g} f_1(x_2, x_3)
f_2(x_1, x_3) f_3(x_1, x_2)$ with $\lVert f_i \rVert_\infty \le 1$
(where $f_i : G \times G \to \mathbb{C}$), still coincide when the
third kernel is required to depend only on $x_1 + x_2$?

Green guesses that the answer is probably 'no'.
-/
@[category research solved, AMS 5 11, formal_proof using formal_conjectures at
"https://github.com/mo271/formal-conjectures/blob/f5afe85e1e02611f63c32ae041b33c67b7938cba/FormalConjectures/GreensOpenProblems/57.lean#L1120"]
theorem green_57 :
answer(False) ↔
∀ (G : Type) [AddCommGroup G] [Fintype G] [DecidableEq G],
Φ G = Φ' G := by
sorry



end

end Green57
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