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2.cpp
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37 lines (34 loc) · 1.06 KB
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/* You are given two non - empty linked lists representing two non - negative integers.
* The digits are stored in reverse order, and each of their nodes contains a single digit.
* Add the two numbersand return the sum as a linked list.
*/
/*
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
int carry = 0;
ListNode head;
ListNode* sum = &head;
while (l1 || l2) {
int val = carry + (l1 ? l1->val : 0) + (l2 ? l2->val : 0);
carry = val / 10;
sum->next = new ListNode(val % 10);
sum = sum->next;
l1 = (l1 ? l1->next : nullptr);
l2 = (l2 ? l2->next : nullptr);
}
if (carry) {
sum->next = new ListNode(carry);
}
return head.next;
}
};