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Copy pathLongest consecutive subsequence
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97 lines (81 loc) · 2.25 KB
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//{ Driver Code Starts
//Initial Template for Java
import java.math.*;
import java.util.*;
import java.io.*;
class Driverclass
{
// Driver Code
static class FastReader{
BufferedReader br;
StringTokenizer st;
public FastReader(){
br = new BufferedReader(new InputStreamReader(System.in));
}
String next(){
while (st == null || !st.hasMoreElements()){
try{ st = new StringTokenizer(br.readLine()); } catch (IOException e){ e.printStackTrace(); }
}
return st.nextToken();
}
String nextLine(){
String str = "";
try{ str = br.readLine(); } catch (IOException e) { e.printStackTrace(); }
return str;
}
Integer nextInt(){
return Integer.parseInt(next());
}
}
public static void main(String args[])
{
FastReader sc = new FastReader();
PrintWriter out = new PrintWriter(System.out);
int t = sc.nextInt();
while(t>0)
{
int n = sc.nextInt();
int a[] = new int[n];
for(int i=0; i<n; i++)
a[i] = sc.nextInt();
out.println(new Solution().findLongestConseqSubseq(a, n));
t--;
}
out.close();
}
}
// } Driver Code Ends
//User function Template for Java
class Solution
{
// arr[] : the input array
// N : size of the array arr[]
//Function to return length of longest subsequence of consecutive integers.
static int findLongestConseqSubseq(int arr[], int N)
{
int n = arr.length;
if (n == 0)
return 0;
int longest = 1;
Set<Integer> set = new HashSet<>();
// put all the array elements into set
for (int i = 0; i < n; i++) {
set.add(arr[i]);
}
// Find the longest sequence
for (int it : set) {
// if 'it' is a starting number
if (!set.contains(it - 1)) {
// find consecutive numbers
int cnt = 1;
int x = it;
while (set.contains(x + 1)) {
x = x + 1;
cnt = cnt + 1;
}
longest = Math.max(longest, cnt);
}
}
return longest;
}
}